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x^2-11x+10=5395
We move all terms to the left:
x^2-11x+10-(5395)=0
We add all the numbers together, and all the variables
x^2-11x-5385=0
a = 1; b = -11; c = -5385;
Δ = b2-4ac
Δ = -112-4·1·(-5385)
Δ = 21661
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{21661}}{2*1}=\frac{11-\sqrt{21661}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{21661}}{2*1}=\frac{11+\sqrt{21661}}{2} $
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